scala - Too many arguments for method mapping: (apply: (String, models.Address) => R)(unapply: R => Option[(String, models.Address)])play.api.data.Mapping[R] -

i have 2 case classes this.

case class company(name: string, address: address) case class address(address1: string, address2: string,                     city: string, state: string,                     zip:string, country: string) 

in application.scala defined following.

[1]. val companyform = form(of(company.apply _, company.unapply _)(     "name" -> text,     "address" -> mapping(         "address1" -> nonemptytext,         "address2" -> text,         "city" -> nonemptytext,         "state" -> nonemptytext,         "zip" -> nonemptytext,         "country" -> nonemptytext     )(address.apply)(address.unapply)   ) )  [2]. val companyform = form(mapping(     "name" -> text,     "address" -> mapping(         "address1" -> nonemptytext,         "address2" -> text,         "city" -> nonemptytext,         "state" -> nonemptytext,         "zip" -> nonemptytext,         "country" -> nonemptytext     )(address.apply)(address.unapply)   )(company.apply, company.unapply) ) 

right [1] works me when try convert [2] gives me following error:

too many arguments method mapping: (apply: (string, models.address) => r)(unapply: r => option[(string, models.address)])play.api.data.mapping[r].

please suggest me doing wrong. in advance.

as methode of() depricated, form must this:

     val companyform = form(     mapping(     "name" -> text,     "address" -> mapping(       "address1" -> nonemptytext,       "address2" -> text,       "city" -> nonemptytext,       "state" -> nonemptytext,       "zip" -> nonemptytext,       "country" -> nonemptytext     )(address.apply)(address.unapply)   )(company.apply)(company.unapply)   ) 

so problem in syntax bellow company.apply , company.unapply methods