linux - Array of array of string in c with malloc -

can tell me doing wrong here ? don't text when print printf("%s\n",text[0]);

i created char **text; , malloced pointers.

#include<stdio.h> #include<string.h> #include<stdlib.h>   char **text;  int main() {     int i;      text = malloc(20000);       for(i=0; < 20000; i++) {         text[i] = malloc(4);          memcpy(text[i], "test",4);     }     printf("%s\n",text[0]);     printf("%s\n",text[1]); } 

i believe you're looking this:

int numelements = 20000, i; // allocate array of char pointers text = malloc(numelements * sizeof( char *));   for( = 0; < numelements; i++) {     // 4 length of string "test", plus 1 additional \0 (null byte)     text[i] = malloc( (4 + 1) * sizeof( char));     memcpy( text[i], "test\0", 5); } 

here online demo showing working, produces output:

test test